sp2 HYBRIDIZATION OF CARBON
The electronic configuration of carbon in its ground state is:
Ground state |
The promotion of one of the two 2s electrons to the empty pz orbital give the excited state.
Excited state |
At this point we follow a different course than that used for sp3
hybridization, in which case one 2s and three 2p orbitals were mixed.
Instead, the 2s electron and just two of three 2p orbitals are mixed or
hybridized to give three new equivalent orbitals. These new orbitals are
referred to as sp2 orbitals, because they are formed by interaction of one s and two p orbitals. Third 2pz orbital is left unhybridized. The electronic configuration of the carbon atom in its sp2 hybridized state is:
Hybridized state |
Each sp2 orbital has an unpaired electron. The shape of sp2 orbital is similar to that of an sp3 orbital.
Formation of three equivalent sp2 orbitals |
The sp2
orbitals obtained are identical, that is, they have the same energy and
shape. They differ only in their orientation in space with respect to
each other. The three sp2
orbitals lie in the same plane with their axes directed towards the
corners of an equilateral triangle. The angle between any pair of
orbitals is 120°.
Orientation of three sp2 orbitals |
The
smaller lobes are not indicated because they do not extend sufficiently
far from nucleus to participate in bond formation. The trigonal
arrangement is favoured because it allows the sp2 orbitals to stay as far apart from each other as possible and thereby reducing the electron-electron repulsion.
The unhybridized pz orbital is oriented along an axis perpendicular to the plane of sp2 orbitals, with each lobe above and below the plane of the sp2 orbitals.
Orientation of the pz orbital |
Whenever carbon is bonded to three other atoms or groups it always uses sp2 orbitals and a pz orbital to form its bonds. For example, ethylene.
BONDING IN ETHYLENE
Each carbon atom in ethylene (H2C=CH2),
is attached to two hydrogen atoms by single covalent bonds and to
another carbon atom by a double bond. Since each carbon is attached to
three other atoms, it uses sp2 hybrid orbitals and an unhybridized pz orbital to form its bonds.
Bonding in ethylene |
In
ethylene there are four C-H single covalent bonds and one C-C double
bond. Each C-H bond is a sigma bond and results from the overlap of one
sp2 orbital from carbon and 1s orbital from hydrogen.
One of the two bonds in the double bond is also a sigma bond and results from end-to-end overlap of the sp2 orbitals, one from each carbon atom.
The second bond in the double bond is a pi bond results from the lateral overlap of two unhybridized pz orbitals, one from each carbon atom. pz
orbitals can overlap only when all the six atoms lie in the same plane,
that is, the plane of sigma bonds. Like the p orbitals from which it is
formed, a pi bond consists of two equal parts. One part lies above the
plane of the carbons and hydrogens and the other part lies below this
plane. These two parts together make up one pi bond.
Formation of the p bond in ethylene |
Although the C-C double bond is represented by two equivalent lines, remember that one line represents a sigma bond and the other the pi bond.
Double bond in ethylene |
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